Страница 91 номер 224, ГДЗ по алгебре за 9 класс к учебнику Алимова с ответами и решением

1) \(a_{n} = 2n + 3\)
\(a_{1} = 2 \cdot 1 + 3 = 5\)
\(a_{2} = 2 \cdot 2 + 3 = 7\)
\(a_{3} = 2 \cdot 3 + 3 = 9\)

2) \(a_{n} = 1 + 3n\)
\(a_{1} = 1 + 3 \cdot 1 = 4\)
\(a_{2} = 1 + 3 \cdot 2 = 7\)
\(a_{3} = 1 + 3 \cdot 3 = 10\)

3) \(a_{n} = 100 - 10n^{2}\)
\(a_{1} = 100 - 10 \cdot 1 = 90\)
\(a_{2} = 100 - 10 \cdot 2^{2} = 60\)
\(a_{3} = 100 - 10 \cdot 3^{2} = 10\)

4) 

\(a_{n} = \dfrac{n - 2}{3}\)
\(a_{1} = \dfrac{1 - 2}{3} = -\dfrac{1}{3}\)
\(a_{2} = \dfrac{2 - 2}{3} = 0\)
\(a_{3} = \dfrac{3 - 2}{3} = \dfrac{1}{3}\)

5) 

\(a_{n} = \dfrac{1}{n}\)
\(a_{1} = \dfrac{1}{1} = 1\)
\(a_{2} = \dfrac{1}{2}\)
\(a_{3} = \dfrac{1}{3}\)

6) 

\(a_{n} = -n^{3}\)
\(a_{1} = -1^{3} = -1\)
\(a_{2} = -2^{3} = -8\)
\(a_{3} = -3^{3} = -27\)