Страница 30, ГДЗ по математике за 1-4 класс к контрольным работам Волковой. Школа России
2 класс. Итоговая контрольная работа за III четверть. Вариант 2
\[\begin{aligned} 3 \cdot 5 &= \textcolor{#e03131}{\mathbf{15}} & \qquad 2 \cdot 8 &= \textcolor{#e03131}{\mathbf{16}} & \qquad 14 : 2 &= \textcolor{#e03131}{\mathbf{7}} & \qquad 15 : 3 &= \textcolor{#e03131}{\mathbf{5}} \\ 9 \cdot 2 &= \textcolor{#e03131}{\mathbf{18}} & \qquad 3 \cdot 3 &= \textcolor{#e03131}{\mathbf{9}} & \qquad 12 : 3 &= \textcolor{#e03131}{\mathbf{4}} & \qquad 21 : 3 &= \textcolor{#e03131}{\mathbf{7}} \\ 7 \cdot 2 &= \textcolor{#e03131}{\mathbf{14}} & \qquad 3 \cdot 9 &= \textcolor{#e03131}{\mathbf{27}} & \qquad 18 : 2 &= \textcolor{#e03131}{\mathbf{9}} & \qquad 60 : 10 &= \textcolor{#e03131}{\mathbf{6}} \end{aligned}\]
\[\begin{aligned} 53 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 61}}}{+} 8 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 60 & \qquad \overset{\textcolor{#808080}{\scriptstyle 44\text{ см}}}{4\text{ дм }4\text{ см}} &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{<}}}}\hspace{0.72em}} \overset{\textcolor{#808080}{\scriptstyle 100\text{ см}}}{1\text{ м}} \end{aligned}\]
\(12 - 5 = \textcolor{#e03131}{\mathbf{7}}\text{ (к.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{7}}\) коржей.
\(1)\ 8 + 9 = \textcolor{#e03131}{\mathbf{17}}\text{ (к.)}\)
\(2)\ 17 - 10 = \textcolor{#e03131}{\mathbf{7}}\text{ (к.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{7}}\) конфет.
\(P = 4 + 2 + 4 + 2 = \textcolor{#e03131}{\mathbf{12}}\text{ (см)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{12}}\) см.
\(1)\ 17 - 9 = \textcolor{#e03131}{\mathbf{8}}\text{ (р.)}\)
\(2)\ 8 - 5 = \textcolor{#e03131}{\mathbf{3}}\text{ (р.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{3}}\) розы.
2 класс. Итоговая контрольная работа за III четверть. Вариант 3
1) \[\begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{1}}8 \\ \smash{\raisebox{0.62em}{$+$}} & 65 \\ \hline & \textcolor{#e03131}{\mathbf{8}\kern-0.075em\mathbf{3}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{6}}2 \\ \smash{\raisebox{0.62em}{$-$}} & 29 \\ \hline & \textcolor{#e03131}{\mathbf{3}\kern-0.075em\mathbf{3}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{4}}0 \\ \smash{\raisebox{0.62em}{$-$}} & 23 \\ \hline & \textcolor{#e03131}{\mathbf{1}\kern-0.075em\mathbf{7}\kern-0.075em} \end{array}\] Проверка: \[\begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{8}}3 \\ \smash{\raisebox{0.62em}{$-$}} & 65 \\ \hline & \textcolor{#e03131}{\mathbf{1}\kern-0.075em\mathbf{8}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{3}}3 \\ \smash{\raisebox{0.62em}{$+$}} & 29 \\ \hline & \textcolor{#e03131}{\mathbf{6}\kern-0.075em\mathbf{2}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{1}}7 \\ \smash{\raisebox{0.62em}{$+$}} & 23 \\ \hline & \textcolor{#e03131}{\mathbf{4}\kern-0.075em\mathbf{0}\kern-0.075em} \end{array}\] 2) \[80 \overset{\textcolor{#1a7f37}{2}}{-} (54 \overset{\textcolor{#1a7f37}{1}}{-} 17) = \textcolor{#e03131}{\mathbf{43}}\] \[\begin{array}{l} \textcolor{#1a7f37}{\mathbf{1)}} \\ \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{5}}4 \\ \smash{\raisebox{0.62em}{$-$}} & 17 \\ \hline & \textcolor{#e03131}{\mathbf{3}\kern-0.075em\mathbf{7}\kern-0.075em} \end{array} \end{array} \qquad \begin{array}{l} \textcolor{#1a7f37}{\mathbf{2)}} \\ \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{8}}0 \\ \smash{\raisebox{0.62em}{$-$}} & 37 \\ \hline & \textcolor{#e03131}{\mathbf{4}\kern-0.075em\mathbf{3}\kern-0.075em} \end{array} \end{array}\]
\[\begin{aligned} 6 \cdot 2 &= \textcolor{#e03131}{\mathbf{12}} & \qquad 2 \cdot 5 &= \textcolor{#e03131}{\mathbf{10}} & \qquad 16 : 2 &= \textcolor{#e03131}{\mathbf{8}} & \qquad 6 : 2 &= \textcolor{#e03131}{\mathbf{3}} \\ 8 \cdot 3 &= \textcolor{#e03131}{\mathbf{24}} & \qquad 3 \cdot 7 &= \textcolor{#e03131}{\mathbf{21}} & \qquad 12 : 2 &= \textcolor{#e03131}{\mathbf{6}} & \qquad 15 : 3 &= \textcolor{#e03131}{\mathbf{5}} \\ 3 \cdot 7 &= \textcolor{#e03131}{\mathbf{21}} & \qquad 9 \cdot 2 &= \textcolor{#e03131}{\mathbf{18}} & \qquad 18 : 3 &= \textcolor{#e03131}{\mathbf{6}} & \qquad 50 : 5 &= \textcolor{#e03131}{\mathbf{10}} \end{aligned}\]
\[\begin{aligned} 52 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 44}}}{-} 8 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 40 & \qquad \overset{\textcolor{#808080}{\scriptstyle 81\text{ мм}}}{8\text{ см }1\text{ мм}} &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 10\text{ мм} \end{aligned}\]
\(12 - 8 = \textcolor{#e03131}{\mathbf{4}}\text{ (ш.)}\)
Ответ: на \(\textcolor{#e03131}{\mathbf{4}}\) шарика.
\(1)\ 80 - 12 = \textcolor{#e03131}{\mathbf{68}}\text{ (п.)}\)
\(2)\ 68 - 8 = \textcolor{#e03131}{\mathbf{60}}\text{ (п.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{60}}\) пачек чая.
\(P = 1 + 3 + 1 + 3 = \textcolor{#e03131}{\mathbf{8}}\text{ (см)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{8}}\) см.