Страница 41, ГДЗ по математике за 1-4 класс к контрольным работам Волковой. Школа России
3 класс. Итоговая контрольная работа за I четверть. Вариант 1
\[\begin{aligned} 36 : 4 \cdot \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{2}}\kern0.035em} &= 18 & \qquad 24 : 6 : \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{2}}\kern0.035em} &= 2 \end{aligned}\]
3 класс. Итоговая контрольная работа за I четверть. Вариант 2
\[\begin{aligned} &\begin{aligned} 1) & & 7 \cdot 3 &= \textcolor{#e03131}{\mathbf{21}} & \qquad 4 \cdot 8 &= \textcolor{#e03131}{\mathbf{32}} & \qquad 7 \cdot 6 &= \textcolor{#e03131}{\mathbf{42}} \\ & & 3 \cdot 9 &= \textcolor{#e03131}{\mathbf{27}} & \qquad 5 \cdot 4 &= \textcolor{#e03131}{\mathbf{20}} & \qquad 8 \cdot 7 &= \textcolor{#e03131}{\mathbf{56}} \\ & & 45 : 9 &= \textcolor{#e03131}{\mathbf{5}} & \qquad 24 : 6 &= \textcolor{#e03131}{\mathbf{4}} & \qquad 18 : 3 &= \textcolor{#e03131}{\mathbf{6}} \\ & & 40 : 5 &= \textcolor{#e03131}{\mathbf{8}} & \qquad 28 : 7 &= \textcolor{#e03131}{\mathbf{4}} & \qquad 36 : 4 &= \textcolor{#e03131}{\mathbf{9}} \end{aligned} \\[10pt] &\begin{aligned} 2) & & 74 - 48 &= \textcolor{#e03131}{\mathbf{26}} & \qquad 39 + 56 &= \textcolor{#e03131}{\mathbf{95}} & \qquad 27 \overset{\textcolor{#1a7f37}{2}}{+} (17 \overset{\textcolor{#1a7f37}{1}}{-} 8) &= \textcolor{#e03131}{\mathbf{36}} \end{aligned} \end{aligned}\]
\[\begin{aligned} x - 32 &= 9 & \qquad 28 + x &= 98 \\ x &= 9 + 32 & \qquad x &= 98 - 28 \\ x &= \textcolor{#e03131}{\mathbf{41}} & \qquad x &= \textcolor{#e03131}{\mathbf{70}} \end{aligned}\]
\(1)\ 12 + 18 = \textcolor{#e03131}{\mathbf{30}}\text{ (к.)}\)
\(2)\ 58 - 30 = \textcolor{#e03131}{\mathbf{28}}\text{ (к.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{28}}\) маленьких календарей.
\(20 : 4 = \textcolor{#e03131}{\mathbf{5}}\text{ (м.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{5}}\) цветных мелков.
\[{\hspace{0.673em}\mathrlap{\textcolor{#e03131}{\raisebox{0.305em}{\rule{10.09em}{0.09em}}}}\mathrlap{\textcolor{#e03131}{\raisebox{0em}{\rule{0.09em}{0.7em}}}}\hspace{10em}\mathrlap{\textcolor{#e03131}{\raisebox{0em}{\rule{0.09em}{0.7em}}}}\hspace{-5em}\mathrlap{\textcolor{#e03131}{\raisebox{0em}{\rule{0.09em}{0.7em}}}}\hspace{-4.955em}\textcolor{#e03131}{\mathclap{\raisebox{0.88em}{\textbf{\textit{M}}}}}\hspace{5em}\textcolor{#e03131}{\mathclap{\raisebox{0.88em}{\textbf{\textit{O}}}}}\hspace{5em}\textcolor{#e03131}{\mathclap{\raisebox{0.88em}{\textbf{\textit{K}}}}}\hspace{0.718em}}\]
\(OK = \textcolor{#e03131}{\mathbf{5}}\text{ см}\)
Отрезков \(\textcolor{#e03131}{\mathbf{3}}\): \(MK\), \(MO\), \(OK\).
\[\begin{aligned} 20 : \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{4}}\kern0.035em} \cdot 2 &= 10 & \qquad 2 \cdot 4 \cdot \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{3}}\kern0.035em} &= 24 \end{aligned}\]
3 класс. Итоговая контрольная работа за I четверть. Вариант 3
\[\begin{aligned} &\begin{aligned} 1) & & 8 \cdot 4 &= \textcolor{#e03131}{\mathbf{32}} & \qquad 4 \cdot 5 &= \textcolor{#e03131}{\mathbf{20}} & \qquad 5 \cdot 7 &= \textcolor{#e03131}{\mathbf{35}} \\ & & 3 \cdot 8 &= \textcolor{#e03131}{\mathbf{24}} & \qquad 9 \cdot 4 &= \textcolor{#e03131}{\mathbf{36}} & \qquad 7 \cdot 7 &= \textcolor{#e03131}{\mathbf{49}} \\ & & 54 : 9 &= \textcolor{#e03131}{\mathbf{6}} & \qquad 28 : 4 &= \textcolor{#e03131}{\mathbf{7}} & \qquad 21 : 3 &= \textcolor{#e03131}{\mathbf{7}} \\ & & 48 : 6 &= \textcolor{#e03131}{\mathbf{8}} & \qquad 16 : 4 &= \textcolor{#e03131}{\mathbf{4}} & \qquad 27 : 9 &= \textcolor{#e03131}{\mathbf{3}} \end{aligned} \\[10pt] &\begin{aligned} 2) & & 63 - 39 &= \textcolor{#e03131}{\mathbf{24}} & \qquad 57 + 28 &= \textcolor{#e03131}{\mathbf{85}} & \qquad 34 \overset{\textcolor{#1a7f37}{2}}{+} (16 \overset{\textcolor{#1a7f37}{1}}{-} 9) &= \textcolor{#e03131}{\mathbf{41}} \end{aligned} \end{aligned}\]
\[\begin{aligned} x + 12 &= 24 & \qquad 58 - x &= 8 \\ x &= 24 - 12 & \qquad x &= 58 - 8 \\ x &= \textcolor{#e03131}{\mathbf{12}} & \qquad x &= \textcolor{#e03131}{\mathbf{50}} \end{aligned}\]
\(1)\ 8 + 22 = \textcolor{#e03131}{\mathbf{30}}\text{ (р.)}\)
\(2)\ 66 - 30 = \textcolor{#e03131}{\mathbf{36}}\text{ (р.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{36}}\) р.
\(6 \cdot 3 = \textcolor{#e03131}{\mathbf{18}}\text{ (к.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{18}}\) кексов.