5класс

Страница 47, ГДЗ за 5 класс к математическому тренажеру Жохова

Задание 26. Сложение и вычитание обыкновенных дробей с одинаковыми знаменателями

Страница 47.

Г \[\begin{aligned} 1\frac{1}{3} + \frac{1}{3} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{2}{3}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{2}{3}}}}}} \\ 2\frac{9}{11} - 1\frac{2}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{7}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{7}{11}}}}}} \\ 8 - 6\frac{5}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{2}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{2}{7}}}}}} \\ 3\frac{8}{17} + 1\frac{7}{17} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{4\frac{15}{17}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{4\frac{15}{17}}}}}} \\ 7 - \frac{7}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{6\frac{4}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{6\frac{4}{11}}}}}} \\[10pt] 4\frac{5}{13} - 2\frac{2}{13} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{2\frac{3}{13}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2\frac{3}{13}}}}}} \\ \frac{4}{7} + \frac{3}{7} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1}}}}} \\ \frac{7}{9} + 2\frac{2}{9} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{3}}}}} \\ 1 - \frac{2}{5} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{3}{5}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{3}{5}}}}}} \\ 3\frac{2}{7} + 5\frac{4}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{8\frac{6}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{8\frac{6}{7}}}}}} \\[10pt] \frac{3}{8} + 3 &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{3\frac{3}{8}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{3\frac{3}{8}}}}}} \\ 3 - \frac{2}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{2\frac{5}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2\frac{5}{7}}}}}} \\ \frac{8}{11} + \frac{7}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{4}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{4}{11}}}}}} \\ 9 - 6\frac{2}{9} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{2\frac{7}{9}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2\frac{7}{9}}}}}} \\ 13\frac{7}{15} - 7 &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{6\frac{7}{15}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{6\frac{7}{15}}}}}} \end{aligned}\]

Д \[\begin{aligned} \frac{5}{7} + 3\frac{6}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{4\frac{4}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{4\frac{4}{7}}}}}} \\ 1\frac{6}{11} - \frac{7}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{10}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{10}{11}}}}}} \\ \frac{9}{15} + \frac{7}{15} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{1}{15}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{1}{15}}}}}} \\ 9 - 3\frac{7}{8} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{5\frac{1}{8}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{5\frac{1}{8}}}}}} \\ 6\frac{6}{13} - 5\frac{11}{13} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{8}{13}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{8}{13}}}}}} \\[10pt] 2\frac{15}{19} + 1\frac{5}{19} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{4\frac{1}{19}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{4\frac{1}{19}}}}}} \\ 1\frac{5}{7} - \frac{6}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{6}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{6}{7}}}}}} \\ \frac{19}{21} + \frac{9}{21} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{7}{21}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{7}{21}}}}}} \\ 9\frac{1}{7} - 2\frac{5}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{6\frac{3}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{6\frac{3}{7}}}}}} \\ 6\frac{8}{9} + 7\frac{5}{9} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{14\frac{4}{9}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{14\frac{4}{9}}}}}} \\[10pt] \frac{6}{7} + \frac{5}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{4}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{4}{7}}}}}} \\ 5\frac{3}{8} - 3 &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{2\frac{3}{8}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2\frac{3}{8}}}}}} \\ 7\frac{9}{17} + 8\frac{8}{17} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{16}}}}} \\ 9\frac{3}{13} - 8\frac{9}{13} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{7}{13}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{7}{13}}}}}} \\ 1\frac{6}{11} - \frac{7}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{10}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{10}{11}}}}}} \end{aligned}\]

Е \[\begin{aligned} \frac{3}{5} + 2\frac{4}{5} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{3\frac{2}{5}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{3\frac{2}{5}}}}}} \\ 8 - 6\frac{9}{10} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{1}{10}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{1}{10}}}}}} \\ 1\frac{4}{9} - \frac{5}{9} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{8}{9}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{8}{9}}}}}} \\ 8\frac{2}{7} - 3\frac{4}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{4\frac{5}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{4\frac{5}{7}}}}}} \\ 3\frac{12}{17} + 2\frac{6}{17} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{6\frac{1}{17}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{6\frac{1}{17}}}}}} \\[10pt] 7\frac{5}{9} - 6\frac{7}{9} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{7}{9}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{7}{9}}}}}} \\ \frac{9}{13} + \frac{7}{13} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{3}{13}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{3}{13}}}}}} \\ 8\frac{8}{13} + 6\frac{5}{13} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{15}}}}} \\ 1\frac{3}{5} - \frac{4}{5} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{4}{5}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{4}{5}}}}}} \\ \frac{7}{11} + \frac{8}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{4}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{4}{11}}}}}} \\[10pt] 6\frac{4}{9} - 4 &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{2\frac{4}{9}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2\frac{4}{9}}}}}} \\ 5\frac{9}{17} + 7\frac{12}{17} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{13\frac{4}{17}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{13\frac{4}{17}}}}}} \\ 1\frac{8}{13} - \frac{9}{13} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{12}{13}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{12}{13}}}}}} \\ \frac{10}{16} + \frac{9}{16} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{3}{16}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{3}{16}}}}}} \\ 8\frac{3}{11} - 7\frac{5}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{9}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{9}{11}}}}}} \end{aligned}\]

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