5класс

Страница 46, ГДЗ за 5 класс к математическому тренажеру Жохова

Задание 26. Сложение и вычитание обыкновенных дробей с одинаковыми знаменателями

26. Вычисли.

А \[\begin{aligned} \frac{2}{5} + \frac{1}{5} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{3}{5}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{3}{5}}}}}} \\ \frac{8}{17} + \frac{5}{17} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{13}{17}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{13}{17}}}}}} \\ \frac{7}{9} + \frac{2}{9} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1}}}}} \\ \frac{9}{10} + \frac{2}{10} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{1}{10}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{1}{10}}}}}} \\ \frac{7}{17} + \frac{9}{17} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{16}{17}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{16}{17}}}}}} \\[10pt] \frac{6}{10} - \frac{3}{10} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{3}{10}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{3}{10}}}}}} \\ \frac{3}{5} + \frac{2}{5} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1}}}}} \\ \frac{10}{11} - \frac{3}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{7}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{7}{11}}}}}} \\ \frac{5}{7} - \frac{4}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{1}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{1}{7}}}}}} \\ \frac{27}{100} + \frac{6}{100} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{33}{100}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{33}{100}}}}}} \\[10pt] \frac{2}{7} + \frac{5}{7} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1}}}}} \\ \frac{5}{11} + \frac{4}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{9}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{9}{11}}}}}} \\ \frac{9}{10} - \frac{6}{10} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{3}{10}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{3}{10}}}}}} \\ \frac{87}{100} - \frac{20}{100} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{67}{100}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{67}{100}}}}}} \\ \frac{14}{15} - \frac{7}{15} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{7}{15}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{7}{15}}}}}} \end{aligned}\]

Б \[\begin{aligned} \frac{3}{7} + \frac{2}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{5}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{5}{7}}}}}} \\ \frac{7}{10} + \frac{2}{10} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{9}{10}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{9}{10}}}}}} \\ \frac{13}{15} - \frac{6}{15} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{7}{15}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{7}{15}}}}}} \\ \frac{8}{11} + \frac{3}{11} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1}}}}} \\ \frac{23}{100} - \frac{10}{100} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{13}{100}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{13}{100}}}}}} \\[10pt] \frac{24}{31} - \frac{7}{31} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{17}{31}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{17}{31}}}}}} \\ \frac{8}{10} - \frac{5}{10} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{3}{10}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{3}{10}}}}}} \\ \frac{17}{23} - \frac{8}{23} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{9}{23}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{9}{23}}}}}} \\ \frac{5}{6} + \frac{1}{6} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1}}}}} \\ \frac{9}{11} - \frac{7}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{2}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{2}{11}}}}}} \\[10pt] \frac{38}{100} + \frac{9}{100} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{47}{100}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{47}{100}}}}}} \\ \frac{8}{11} - \frac{3}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{5}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{5}{11}}}}}} \\ \frac{2}{10} + \frac{5}{10} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{7}{10}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{7}{10}}}}}} \\ \frac{16}{19} - \frac{7}{19} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{9}{19}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{9}{19}}}}}} \\ \frac{1}{3} + \frac{2}{3} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1}}}}} \end{aligned}\]

В \[\begin{aligned} \frac{3}{5} + \frac{4}{5} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{1\frac{2}{5}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\frac{2}{5}}}}}} \\ 1 - \frac{2}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{\frac{5}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{\frac{5}{7}}}}}} \\ 4\frac{2}{5} + 2\frac{1}{5} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{6\frac{3}{5}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{6\frac{3}{5}}}}}} \\ 3\frac{8}{11} - 1\frac{6}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{2\frac{2}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2\frac{2}{11}}}}}} \\ \frac{5}{7} + 2 &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{2\frac{5}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2\frac{5}{7}}}}}} \\[10pt] 2\frac{3}{8} + \frac{5}{8} &= \boxed{\vphantom{\mathbf{\frac{1}{1}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{3}}}}} \\ 3\frac{2}{7} + \frac{4}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{3\frac{6}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{3\frac{6}{7}}}}}} \\ 6 - 2\frac{1}{3} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{3\frac{2}{3}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{3\frac{2}{3}}}}}} \\ 4\frac{18}{23} + 2\frac{3}{23} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{6\frac{21}{23}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{6\frac{21}{23}}}}}} \\ 5 - \frac{5}{11} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{4\frac{6}{11}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{4\frac{6}{11}}}}}} \\[10pt] 7 - 2\frac{3}{7} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{4\frac{4}{7}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{4\frac{4}{7}}}}}} \\ 2\frac{5}{13} + 3\frac{7}{13} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{5\frac{12}{13}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{5\frac{12}{13}}}}}} \\ \frac{1}{5} + 3\frac{2}{5} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{3\frac{3}{5}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{3\frac{3}{5}}}}}} \\ 4 - \frac{1}{6} &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{3\frac{5}{6}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{3\frac{5}{6}}}}}} \\ 11\frac{3}{14} - 3 &= \boxed{\vphantom{\textcolor{#e03131}{\mathbf{8\frac{3}{14}}}}\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{8\frac{3}{14}}}}}} \end{aligned}\]

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