Страница 41, ГДЗ за 5 класс к математическому тренажеру Жохова

Г \[\begin{array}{l} \hspace{0.8em}\begin{array}{l} \mathllap{1)\ }a = 25\text{ дм} \\ b = 2\text{ м} \\ \underline{\mathrlap{c = 8\text{ дм}}\hphantom{a = 25\text{ дм}}} \\ V = 25 \cdot 20 \cdot 8 = \textcolor{#e03131}{\mathbf{4\,000}}\text{ (дм}^3\text{)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{2\text{ м}= 20\text{ дм.}} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{2)\ }a = 3\text{ дм} \\ b = 10\text{ см} \\ \underline{\mathrlap{c = 19\text{ см}}\hphantom{b = 10\text{ см}}} \\ V = 30 \cdot 10 \cdot 19 = \textcolor{#e03131}{\mathbf{5\,700}}\text{ (см}^3\text{)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{3\text{ дм}= 30\text{ см.}} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{3)\ }a = 6\text{ м} \\ b = 20\text{ дм} \\ \underline{\mathrlap{c = 50\text{ см}}\hphantom{b = 20\text{ дм}}} \\ V = 60 \cdot 20 \cdot 5 = \textcolor{#e03131}{\mathbf{6\,000}}\text{ (дм}^3\text{)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{6\text{ м}= 60\text{ дм, }50\text{ см}= 5\text{ дм.}} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{4)\ }a = 8\text{ м} \\ b = 70\text{ дм} \\ \underline{\mathrlap{c = 125\text{ м}}\hphantom{b = 70\text{ дм}}} \\ V = 8 \cdot 7 \cdot 125 = \textcolor{#e03131}{\mathbf{7\,000}}\text{ (м}^3\text{)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{70\text{ дм}= 7\text{ м.}} \end{array} \end{array}\]

Д \[\begin{array}{l} \hspace{0.8em}\begin{array}{l} \mathllap{1)\ }b = 4\text{ см} \\ c = 13\text{ см} \\ \underline{V = 104\text{ см}^3} \\ a = 104 : (4 \cdot 13) = \textcolor{#e03131}{\mathbf{2}}\text{ (см)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{2)\ }a = 30\text{ см} \\ c = 17\text{ дм} \\ \underline{V = 1\,020\text{ дм}^3} \\ b = 1\,020 : (3 \cdot 17) = \textcolor{#e03131}{\mathbf{20}}\text{ (дм)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{30\text{ см}= 3\text{ дм.}} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{3)\ }S = 40\text{ дм}^2 \\ \underline{\mathrlap{h = 5\text{ дм}}\hphantom{S = 40\text{ дм}^2}} \\ V = 40 \cdot 5 = \textcolor{#e03131}{\mathbf{200}}\text{ (дм}^3\text{)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{4)\ }V = 15\text{ м}^3 \\ \underline{\mathrlap{h = 3\text{ м}}\hphantom{V = 15\text{ м}^3}} \\ S = 15 : 3 = \textcolor{#e03131}{\mathbf{5}}\text{ (м}^2\text{)} \end{array} \end{array}\]

Е \[\begin{array}{l} \hspace{0.8em}\begin{array}{l} \mathllap{1)\ }a = 8\text{ дм} \\ b = 6\text{ дм} \\ \underline{V = 96\text{ дм}^3} \\ c = 96 : (8 \cdot 6) = \textcolor{#e03131}{\mathbf{2}}\text{ (дм)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{2)\ }a = 1\text{ м} \\ c = 19\text{ дм} \\ \underline{V = 1\,140\text{ дм}^3} \\ b = 1\,140 : (10 \cdot 19) = \textcolor{#e03131}{\mathbf{6}}\text{ (дм)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{1\text{ м}= 10\text{ дм.}} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{3)\ }V = 160\text{ дм}^3 \\ \underline{\mathrlap{h = 20\text{ дм}}\hphantom{V = 160\text{ дм}^3}} \\ S = 160 : 20 = \textcolor{#e03131}{\mathbf{8}}\text{ (дм}^2\text{)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{4)\ }h = 4\text{ м} \\ \underline{S = 60\text{ м}^2} \\ V = 60 \cdot 4 = \textcolor{#e03131}{\mathbf{240}}\text{ (м}^3\text{)} \end{array} \end{array}\]