Страница 40, ГДЗ за 5 класс к математическому тренажеру Жохова

А \[\begin{array}{l} \hspace{0.8em}\begin{array}{l} \mathllap{1)\ }a = 9\text{ м} \\ b = 14\text{ м} \\ \underline{\mathrlap{c = 5\text{ м}}\hphantom{b = 14\text{ м}}} \\ V = 9 \cdot 14 \cdot 5 = \textcolor{#e03131}{\mathbf{630}}\text{ (м}^3\text{)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{2)\ }a = 20\text{ дм} \\ b = 15\text{ дм} \\ \underline{\mathrlap{c = 2\text{ дм}}\hphantom{a = 20\text{ дм}}} \\ V = 20 \cdot 15 \cdot 2 = \textcolor{#e03131}{\mathbf{600}}\text{ (дм}^3\text{)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{3)\ }a = 7\text{ см} \\ b = 10\text{ см} \\ \underline{\mathrlap{c = 8\text{ см}}\hphantom{b = 10\text{ см}}} \\ V = 7 \cdot 10 \cdot 8 = \textcolor{#e03131}{\mathbf{560}}\text{ (см}^3\text{)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{4)\ }a = 19\text{ дм} \\ b = 25\text{ дм} \\ \underline{\mathrlap{c = 4\text{ дм}}\hphantom{a = 19\text{ дм}}} \\ V = 19 \cdot 25 \cdot 4 = \textcolor{#e03131}{\mathbf{1\,900}}\text{ (дм}^3\text{)} \end{array} \end{array}\]

Б \[\begin{array}{l} \hspace{0.8em}\begin{array}{l} \mathllap{1)\ }a = 9\text{ м} \\ b = 10\text{ м} \\ \underline{\mathrlap{c = 8\text{ м}}\hphantom{b = 10\text{ м}}} \\ V = 9 \cdot 10 \cdot 8 = \textcolor{#e03131}{\mathbf{720}}\text{ (м}^3\text{)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{2)\ }a = 30\text{ см} \\ b = 6\text{ дм} \\ \underline{\mathrlap{c = 5\text{ м}}\hphantom{a = 30\text{ см}}} \\ V = 3 \cdot 6 \cdot 50 = \textcolor{#e03131}{\mathbf{900}}\text{ (дм}^3\text{)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{30\text{ см}= 3\text{ дм, }5\text{ м}= 50\text{ дм.}} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{3)\ }a = 6\text{ см} \\ b = 5\text{ см} \\ \underline{\mathrlap{c = 3\text{ см}}\hphantom{a = 6\text{ см}}} \\ V = 6 \cdot 5 \cdot 3 = \textcolor{#e03131}{\mathbf{90}}\text{ (см}^3\text{)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{4)\ }a = 16\text{ см} \\ b = 7\text{ см} \\ \underline{\mathrlap{c = 5\text{ см}}\hphantom{a = 16\text{ см}}} \\ V = 16 \cdot 7 \cdot 5 = \textcolor{#e03131}{\mathbf{560}}\text{ (см}^3\text{)} \end{array} \end{array}\]

В \[\begin{array}{l} \hspace{0.8em}\begin{array}{l} \mathllap{1)\ }a = 2\text{ м} \\ b = 5\text{ м} \\ \underline{\mathrlap{c = 4\text{ м}}\hphantom{a = 2\text{ м}}} \\ V = 2 \cdot 5 \cdot 4 = \textcolor{#e03131}{\mathbf{40}}\text{ (м}^3\text{)} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{2)\ }a = 17\text{ дм} \\ b = 3\text{ м} \\ \underline{\mathrlap{c = 10\text{ дм}}\hphantom{a = 17\text{ дм}}} \\ V = 17 \cdot 30 \cdot 10 = \textcolor{#e03131}{\mathbf{5\,100}}\text{ (дм}^3\text{)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{3\text{ м}= 30\text{ дм.}} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{3)\ }a = 3\text{ дм} \\ b = 125\text{ см} \\ \underline{\mathrlap{c = 8\text{ см}}\hphantom{b = 125\text{ см}}} \\ V = 30 \cdot 125 \cdot 8 = \textcolor{#e03131}{\mathbf{30\,000}}\text{ (см}^3\text{)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{3\text{ дм}= 30\text{ см.}} \end{array} \\ \\ \hspace{0.8em}\begin{array}{l} \mathllap{4)\ }a = 10\text{ см} \\ b = 15\text{ см} \\ \underline{\mathrlap{c = 4\text{ дм}}\hphantom{a = 10\text{ см}}} \\ V = 10 \cdot 15 \cdot 40 = \textcolor{#e03131}{\mathbf{6\,000}}\text{ (см}^3\text{)} \\ \rule{0pt}{1.1em}\textcolor{#808080}{4\text{ дм}= 40\text{ см.}} \end{array} \end{array}\]