Страница 44, ГДЗ по математике за 4 класс к самостоятельным и контрольным работам Лопатковой
Умножение и деление на однозначное число. Самостоятельная работа № 16. Вариант 1
\[\begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{32}196 & \underline{\,4\phantom{000}\,} \\ \underline{32}\phantom{000} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{8}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{0}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{4}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{9}\kern-0.075em}} \\ \phantom{00}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}19\phantom{0} & \\ \phantom{00}\underline{16}\phantom{0} & \\ \phantom{000}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}36 & \\ \phantom{000}\underline{36} & \\ \phantom{0000}0 & \end{array} \qquad \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{48}408 & \underline{\,8\phantom{000}\,} \\ \underline{48}\phantom{000} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{6}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{0}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{5}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{1}\kern-0.075em}} \\ \phantom{00}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}40\phantom{0} & \\ \phantom{00}\underline{40}\phantom{0} & \\ \phantom{0000}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}8 & \\ \phantom{0000}\underline{8} & \\ \phantom{0000}0 & \end{array} \qquad \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{22}47 & \underline{\,3\phantom{00}\,} \\ \underline{21}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{7}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{4}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{9}\kern-0.075em}} \\ \phantom{0}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}14\phantom{0} & \\ \phantom{0}\underline{12}\phantom{0} & \\ \phantom{00}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}27 & \\ \phantom{00}\underline{27} & \\ \phantom{000}0 & \end{array}\]
1-й способ:
\(1)\ 7 - 4 = \textcolor{#e03131}{\mathbf{3}}\text{ (м)}\)
\(2)\ 2\,400 : 3 = \textcolor{#e03131}{\mathbf{800}}\text{ (р.)}\)
\(3)\ 7 + 4 = \textcolor{#e03131}{\mathbf{11}}\text{ (м)}\)
\(4)\ 800 \cdot 11 = \textcolor{#e03131}{\mathbf{8\,800}}\text{ (р.)}\)
2-й способ:
\(1)\ 7 - 4 = \textcolor{#e03131}{\mathbf{3}}\text{ (м)}\)
\(2)\ 2\,400 : 3 = \textcolor{#e03131}{\mathbf{800}}\text{ (р.)}\)
\(3)\ 800 \cdot 7 = \textcolor{#e03131}{\mathbf{5\,600}}\text{ (р.)}\)
\(4)\ 800 \cdot 4 = \textcolor{#e03131}{\mathbf{3\,200}}\text{ (р.)}\)
\(5)\ 5\,600 + 3\,200 = \textcolor{#e03131}{\mathbf{8\,800}}\text{ (р.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{8\,800}}\) р.
\[\overset{\textcolor{#808080}{\scriptstyle 28\,350\text{ м}}}{28\text{ км }350\text{ м}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 4\,050\text{ м}}\kern0.25em\rule[-0.35em]{0pt}{0.35em}}{:} 7 = \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{4}}\text{ км }\textcolor{#e03131}{\mathbf{50}}\text{ м}}}}\] \[\overset{\textcolor{#808080}{\scriptstyle 18\,360\text{ кг}}}{18\text{ т }360\text{ кг}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 3\,060\text{ кг}}\kern0.25em\rule[-0.35em]{0pt}{0.35em}}{:} 6 = \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{3}}\text{ т }\textcolor{#e03131}{\mathbf{60}}\text{ кг}}}}\] \[\overset{\textcolor{#808080}{\scriptstyle 13\,100\text{ г}}}{13\text{ кг }100\text{ г}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 65\,500\text{ г}}\kern0.25em\rule[-0.35em]{0pt}{0.35em}}{\cdot} 5 = \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{65}}\text{ кг }\textcolor{#e03131}{\mathbf{500}}\text{ г}}}}\]
Под тремя символами «спрятались» 3 разных числа. Найди их, если:
\(L \cdot R = 36\);
\(R \cdot Z = L\);
\(Z \cdot Z = 81\).
\({L}\) — \({\rule{0pt}{1.23em}\boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{18}}}}}\text{,}}\) \({Z}\) — \({\rule{0pt}{1.23em}\boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{9}}}}}\text{,}}\) \({R}\) — \({\rule{0pt}{1.23em}\boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2}}}}}}\)
\(\textcolor{#808080}{{18 \cdot 2 = 36}\text{, }{2 \cdot 9 = 18}\text{, }{9 \cdot 9 = 81}\text{.}}\)