Страница 43, ГДЗ по математике за 4 класс к самостоятельным и контрольным работам Лопатковой
Умножение и деление на однозначное число. Самостоятельная работа № 15. Вариант 2
\[\begin{aligned} x - 1\,301 &= 3 \cdot 82 \\ x - 1\,301 &= \textcolor{#e03131}{\mathbf{246}} \\ x &= 246 + 1\,301 \\ x &= \textcolor{#e03131}{\mathbf{1\,547}} \\ \text{Проверка: }1\,547 - 1\,301 &= 3 \cdot 82 \\ \textcolor{#e03131}{\mathbf{246}} &= \textcolor{#e03131}{\mathbf{246}} \end{aligned}\] \[\begin{array}{cr} & \vphantom{\overset{\bullet}{0}}1301 \\ \smash{\raisebox{0.62em}{$+$}} & 246 \\ \hline & \textcolor{#e03131}{\mathbf{1}\kern-0.075em\mathbf{5}\kern-0.075em\mathbf{4}\kern-0.075em\mathbf{7}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}1547 \\ \smash{\raisebox{0.62em}{$-$}} & 1301 \\ \hline & \textcolor{#e03131}{\mathbf{2}\kern-0.075em\mathbf{4}\kern-0.075em\mathbf{6}\kern-0.075em} \end{array}\] \[\begin{aligned} 2\,455 - y &= 630 : 6 \\ 2\,455 - y &= \textcolor{#e03131}{\mathbf{105}} \\ y &= 2\,455 - 105 \\ y &= \textcolor{#e03131}{\mathbf{2\,350}} \\ \text{Проверка: }2\,455 - 2\,350 &= 630 : 6 \\ \textcolor{#e03131}{\mathbf{105}} &= \textcolor{#e03131}{\mathbf{105}} \end{aligned}\] \[\begin{array}{cr} & \vphantom{\overset{\bullet}{0}}2455 \\ \smash{\raisebox{0.62em}{$-$}} & 105 \\ \hline & \textcolor{#e03131}{\mathbf{2}\kern-0.075em\mathbf{3}\kern-0.075em\mathbf{5}\kern-0.075em\mathbf{0}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}2455 \\ \smash{\raisebox{0.62em}{$-$}} & 2350 \\ \hline & \textcolor{#e03131}{\mathbf{1}\kern-0.075em\mathbf{0}\kern-0.075em\mathbf{5}\kern-0.075em} \end{array}\]
\[\overset{\textcolor{#808080}{\scriptstyle 21\,324\text{ г}}}{21\text{ кг }324\text{ г}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 7\,108\text{ г}}\kern0.25em\rule[-0.35em]{0pt}{0.35em}}{:} 3 = \underline{\kern0.4em\textcolor{#e03131}{\mathbf{7}}\text{ кг }\textcolor{#e03131}{\mathbf{108}}\text{ г}\kern0.4em}\] \[40\text{ т} : 4 = \underline{\kern0.4em\textcolor{#e03131}{\mathbf{10}}\text{ т}\kern0.4em}\] \[\overset{\textcolor{#808080}{\scriptstyle 496\text{ мм}}}{40\text{ см }96\text{ мм}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 62\text{ мм}}\kern0.25em\rule[-0.35em]{0pt}{0.35em}}{:} 8 = \underline{\kern0.4em\textcolor{#e03131}{\mathbf{6}}\text{ см }\textcolor{#e03131}{\mathbf{2}}\text{ мм}\kern0.4em}\] \(\textcolor{#808080}{{96\text{ мм} = 9\text{ см }6\text{ мм}}\text{,}}\) \(\textcolor{#808080}{\text{поэтому }{40\text{ см }96\text{ мм} = 49\text{ см }6\text{ мм}}\text{.}}\) \[\overset{\textcolor{#808080}{\scriptstyle 1\,218\text{ кг}}}{12\text{ ц }18\text{ кг}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 7\,308\text{ кг}}\kern0.25em\rule[-0.35em]{0pt}{0.35em}}{\cdot} 6 = \underline{\kern0.4em\textcolor{#e03131}{\mathbf{73}}\text{ ц }\textcolor{#e03131}{\mathbf{8}}\text{ кг}\kern0.4em}\] \[\overset{\textcolor{#808080}{\scriptstyle 5\,120\text{ м}}}{5\text{ км }120\text{ м}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 25\,600\text{ м}}\kern0.25em\rule[-0.35em]{0pt}{0.35em}}{\cdot} 5 = \underline{\kern0.4em\textcolor{#e03131}{\mathbf{25}}\text{ км }\textcolor{#e03131}{\mathbf{600}}\text{ м}\kern0.4em}\]
\(1)\ 1\,269 : 3 = \textcolor{#e03131}{\mathbf{423}}\text{ (км)}\)
\(2)\ 423 \cdot 4 = \textcolor{#e03131}{\mathbf{1\,692}}\text{ (км)}\)
\(3)\ 1\,269 + 423 + 1\,692 = \textcolor{#e03131}{\mathbf{3\,384}}\text{ (км)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{3\,384}}\) км.
\[\begin{aligned} 45\,697 \overset{\textcolor{#1a7f37}{4}}{-} (3\,000 \mathbin{\overset{\textcolor{#1a7f37}{1}}{\vphantom{+}\cdot}} 6 \overset{\textcolor{#1a7f37}{3}}{+} 54\,000 \mathrel{\overset{\textcolor{#1a7f37}{2}}{\vphantom{+}{:}}} 2) &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{697}}}}} \end{aligned}\]
