Часть 2 страница 17, ГДЗ по математике за 4 класс к рабочей тетради Дорофеева

\[\begin{array}{c} \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}3197 \\ \smash{\raisebox{0.62em}{$\times$}} & 2 \\ \hline & \textcolor{#e03131}{\mathbf{6}\kern-0.075em\mathbf{3}\kern-0.075em\mathbf{9}\kern-0.075em\mathbf{4}\kern-0.075em} \end{array} \\ \text{Ы} \end{array} \qquad \begin{array}{c} \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}7254 \\ \smash{\raisebox{0.62em}{$\times$}} & 6 \\ \hline & \textcolor{#e03131}{\mathbf{4}\kern-0.075em\mathbf{3}\kern-0.075em\mathbf{5}\kern-0.075em\mathbf{2}\kern-0.075em\mathbf{4}\kern-0.075em} \end{array} \\ \text{А} \end{array} \qquad \begin{array}{c} \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\overgroup{\hphantom{\textstyle 258}}}}}{258} & \underline{\,86\,} \\ \underline{258} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{3}\kern-0.075em}} \\ \phantom{00}0 & \end{array} \\ \text{К} \end{array}\] \[\begin{array}{c} \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{\phantom{0}}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{5}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{7}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{9}}6 \\ \smash{\raisebox{0.62em}{$+$}} & 35428 \\ \hline & \textcolor{#e03131}{\mathbf{4}\kern-0.075em\mathbf{1}\kern-0.075em\mathbf{2}\kern-0.075em\mathbf{2}\kern-0.075em\mathbf{4}\kern-0.075em} \\ & \vphantom{\underline{0}} \\ & \vphantom{\underline{0}} \end{array} \\ \text{Т} \end{array} \qquad \begin{array}{c} \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{9}}1\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{8}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{0}}5 \\ \smash{\raisebox{0.62em}{$-$}} & 86037 \\ \hline & \textcolor{#e03131}{\mathbf{5}\kern-0.075em\mathbf{7}\kern-0.075em\mathbf{6}\kern-0.075em\mathbf{8}\kern-0.075em} \\ & \vphantom{\underline{0}} \\ & \vphantom{\underline{0}} \end{array} \\ \text{Н} \end{array} \qquad \begin{array}{c} \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}28 \\ \smash{\raisebox{0.62em}{$\times$}} & 34 \\ \hline & 112 \\ \smash{\raisebox{0.62em}{$+$}} & 84\phantom{0} \\ \hline & \textcolor{#e03131}{\mathbf{9}\kern-0.075em\mathbf{5}\kern-0.075em\mathbf{2}\kern-0.075em} \end{array} \\ \text{Л} \end{array}\] \[\begin{array}{|c|c|c|c|c|} \hline 43\,524 & 952 & 41\,224 & 6\,394 & 5\,768 \\ \hline \textcolor{#e03131}{\textbf{А}} & \textcolor{#e03131}{\textbf{Л}} & \textcolor{#e03131}{\textbf{Т}} & \textcolor{#e03131}{\textbf{Ы}} & \textcolor{#e03131}{\textbf{Н}} \\ \hline \end{array}\] Значение выражения, которое не вошло в таблицу, указывает достоинство этой монеты в копейках. Запиши его: \({\rule{0pt}{1.23em}\boxed{\smash[b]{\underset{\hspace{2.5em}}{\textcolor{#e03131}{\mathbf{3}}}}}\text{ к.}}\)

\(1)\ 928 \cdot 2 = \textcolor{#e03131}{\mathbf{1\,856}}\text{ (т)}\)
\(2)\ 928 + 1\,856 = \textcolor{#e03131}{\mathbf{2\,784}}\text{ (т)}\)
\(3)\ 3\,456 - 2\,784 = \textcolor{#e03131}{\mathbf{672}}\text{ (т)}\) \[\begin{array}{l} \textcolor{#1a7f37}{\mathbf{1)}} \\ \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}928 \\ \smash{\raisebox{0.62em}{$\times$}} & 2 \\ \hline & \textcolor{#e03131}{\mathbf{1}\kern-0.075em\mathbf{8}\kern-0.075em\mathbf{5}\kern-0.075em\mathbf{6}\kern-0.075em} \end{array} \end{array}\] Ответ: \(\textcolor{#e03131}{\mathbf{672}}\) т.