Часть 2 страница 31, ГДЗ по математике за 2 класс к рабочей тетради Моро

\(2\text{ см} + 1\text{ дм} = 2\text{ см} + 10\text{ см} = \textcolor{#e03131}{\mathbf{12}}\text{ см}\)

\[\begin{aligned} 18 - 9 + \textcolor{#e03131}{\mathbf{6}} &= 15 & \qquad 17 - (15 \mathbin{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{-}}}}\hspace{0.72em}} \textcolor{#e03131}{\mathbf{6}}) &= 8 \\ 13 + 4 \mathbin{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{-}}}}\hspace{0.72em}} \textcolor{#e03131}{\mathbf{9}} &= 8 & \qquad 13 - (11 \mathbin{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{-}}}}\hspace{0.72em}} \textcolor{#e03131}{\mathbf{8}}) &= 10 \\ 15 \mathbin{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{-}}}}\hspace{0.72em}} \textcolor{#e03131}{\mathbf{9}} + 6 &= 12 & \qquad 14 - (12 \mathbin{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{-}}}}\hspace{0.72em}} \textcolor{#e03131}{\mathbf{7}}) &= 9 \end{aligned}\]

Найди периметр каждого прямоугольника.
\(4 + 2 + 4 + 2 = \textcolor{#e03131}{\mathbf{12}}\text{ (см)}\)
\(2 \cdot 4 = \textcolor{#e03131}{\mathbf{8}}\text{ (см)}\)