Часть 2 страница 10, ГДЗ по математике за 2 класс к рабочей тетради Моро
Вычисления вида 92 − 45
\[\begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\textcolor{#e03131}{\mathbf{3}\kern-0.075em}2 \\ \smash{\raisebox{0.62em}{$+$}} & 4\textcolor{#e03131}{\mathbf{6}\kern-0.075em} \\ \hline & 78 \end{array} \quad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}6\textcolor{#e03131}{\mathbf{4}\kern-0.075em} \\ \smash{\raisebox{0.62em}{$-$}} & 12 \\ \hline & \textcolor{#e03131}{\mathbf{5}\kern-0.075em}2 \end{array} \quad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\textcolor{#e03131}{\mathbf{8}\kern-0.075em}8 \\ \smash{\raisebox{0.62em}{$-$}} & 4\textcolor{#e03131}{\mathbf{2}\kern-0.075em} \\ \hline & 46 \end{array} \quad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}6\textcolor{#e03131}{\mathbf{9}\kern-0.075em} \\ \smash{\raisebox{0.62em}{$-$}} & \textcolor{#e03131}{\mathbf{3}\kern-0.075em}5 \\ \hline & 34 \end{array} \quad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}4\textcolor{#e03131}{\mathbf{2}\kern-0.075em} \\ \smash{\raisebox{0.62em}{$+$}} & \textcolor{#e03131}{\mathbf{5}\kern-0.075em}6 \\ \hline & 98 \end{array}\]
\(15 - 4 = \textcolor{#e03131}{\mathbf{11}}\text{ (см)}\)
\(\textcolor{#e03131}{\boldsymbol{11}} \mathrel{\textcolor{#e03131}{\boldsymbol{=}}} \textcolor{#e03131}{\boldsymbol{6 + 5}}\)
Ответ: \(\textcolor{#e03131}{\mathbf{6}}\) см; \(\textcolor{#e03131}{\mathbf{5}}\) см.
\[\begin{aligned} 15 + 8 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{2}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{3}}\kern0.035em} & \qquad 62 + 8 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{7}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} & \qquad 43 - 7 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{3}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{6}}\kern0.035em} \\ 27 + 4 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{3}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{1}}\kern0.035em} & \qquad 85 + 9 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{9}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{4}}\kern0.035em} & \qquad 51 - 3 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{4}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{8}}\kern0.035em} \\ 54 + 6 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{6}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} & \qquad 67 + 6 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{7}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{3}}\kern0.035em} & \qquad 72 - 8 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{6}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{4}}\kern0.035em} \end{aligned}\]
1) сумму, в которой первое слагаемое 24, а второе слагаемое на 4 меньше первого;
2) разность, в которой вычитаемое 46, а уменьшаемое на 4 больше вычитаемого.
1) \(\textcolor{#e03131}{\boldsymbol{24 + 20}} \mathrel{\textcolor{#e03131}{\boldsymbol{=}}} \textcolor{#e03131}{\boldsymbol{44}}\)
2) \(\textcolor{#e03131}{\boldsymbol{50 - 46}} \mathrel{\textcolor{#e03131}{\boldsymbol{=}}} \textcolor{#e03131}{\boldsymbol{4}}\)
