Страница 49, ГДЗ по математике за 4 класс к самостоятельным и контрольным работам Лопатковой
Контрольная работа за первое полугодие. Вариант 2
\[\begin{aligned} 156 \overset{\textcolor{#1a7f37}{4}}{-} 96 \mathrel{\overset{\textcolor{#1a7f37}{2}}{\vphantom{+}{:}}} (12 \mathrel{\overset{\textcolor{#1a7f37}{1}}{\vphantom{+}{:}}} 4) \mathrel{\overset{\textcolor{#1a7f37}{3}}{\vphantom{+}{:}}} 2 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{140}}}}} \end{aligned}\]
\[\begin{aligned} 4\text{ сут. }14\text{ ч} &= \boxed{\smash[b]{\underset{\hspace{2em}}{\textcolor{#e03131}{\mathbf{110}}}}}\text{ ч} & \qquad 23\text{ м }8\text{ дм} &= \boxed{\smash[b]{\underset{\hspace{2em}}{\textcolor{#e03131}{\mathbf{238}}}}}\text{ дм} \\ 23\text{ т }5\text{ ц} &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{23\,500}}}}}\text{ кг} & \qquad 150\,000\text{ см}^2 &= \boxed{\smash[b]{\underset{\hspace{2em}}{\textcolor{#e03131}{\mathbf{15}}}}}\text{ м}^2 \end{aligned}\]
\[\begin{aligned} 126 : x &= 54 : 6 \\ 126 : x &= \textcolor{#e03131}{\mathbf{9}} \\ x &= 126 : 9 \\ x &= \textcolor{#e03131}{\mathbf{14}} \\ \text{Проверка: }126 : 14 &= 54 : 6 \\ \textcolor{#e03131}{\mathbf{9}} &= \textcolor{#e03131}{\mathbf{9}} \end{aligned}\] \[\begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{12}6 & \underline{\,9\phantom{0}\,} \\ \phantom{0}\underline{9}\phantom{0} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{1}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{4}\kern-0.075em}} \\ \phantom{0}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}36 & \\ \phantom{0}\underline{36} & \\ \phantom{00}0 & \end{array}\] \[\begin{aligned} y : (720 : 30) &= 6 \\ y : \textcolor{#e03131}{\mathbf{24}} &= 6 \\ y &= 6 \cdot 24 \\ y &= \textcolor{#e03131}{\mathbf{144}} \\ \text{Проверка: }144 : (720 : 30) &= 6 \\ \textcolor{#e03131}{\mathbf{6}} &= \textcolor{#e03131}{\mathbf{6}} \end{aligned}\]
\(1)\ 43 \cdot 3 = \textcolor{#e03131}{\mathbf{129}}\text{ (км)}\)
\(2)\ 40 \cdot 2 = \textcolor{#e03131}{\mathbf{80}}\text{ (км)}\)
\(3)\ 129 + 80 = \textcolor{#e03131}{\mathbf{209}}\text{ (км)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{209}}\) км.
\[\overset{\textcolor{#808080}{\scriptstyle 3\,349\text{ см}}}{33\text{ м }49\text{ см}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 5\,600\text{ см}}\kern0.25em}{+} \overset{\textcolor{#808080}{\scriptstyle 2\,251\text{ см}}}{22\text{ м }51\text{ см}} = \underline{\kern0.4em\textcolor{#e03131}{\mathbf{56}}\text{ м}\kern0.4em}\]
