Страница 48, ГДЗ по математике за 4 класс к самостоятельным и контрольным работам Лопатковой
Контрольная работа за первое полугодие. Вариант 1
\[\begin{aligned} 5 \mathbin{\overset{\textcolor{#1a7f37}{2}}{\vphantom{+}\cdot}} (125 \overset{\textcolor{#1a7f37}{1}}{+} 75) \mathrel{\overset{\textcolor{#1a7f37}{3}}{\vphantom{+}{:}}} 20 \overset{\textcolor{#1a7f37}{4}}{+} 80 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{130}}}}} \end{aligned}\]
\[\begin{aligned} 32\text{ дм }8\text{ см} &= \boxed{\smash[b]{\underset{\hspace{2em}}{\textcolor{#e03131}{\mathbf{328}}}}}\text{ см} & \qquad 32\text{ м}^2 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{320\,000}}}}}\text{ см}^2 \\ 5\text{ ч }28\text{ мин} &= \boxed{\smash[b]{\underset{\hspace{2em}}{\textcolor{#e03131}{\mathbf{328}}}}}\text{ мин} & \qquad 15\text{ т }2\text{ ц} &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{15\,200}}}}}\text{ кг} \end{aligned}\]
\[\begin{aligned} 112 : x &= 48 : 6 \\ 112 : x &= \textcolor{#e03131}{\mathbf{8}} \\ x &= 112 : 8 \\ x &= \textcolor{#e03131}{\mathbf{14}} \\ \text{Проверка: }112 : 14 &= 48 : 6 \\ \textcolor{#e03131}{\mathbf{8}} &= \textcolor{#e03131}{\mathbf{8}} \end{aligned}\] \[\begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{11}2 & \underline{\,8\phantom{0}\,} \\ \phantom{0}\underline{8}\phantom{0} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{1}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{4}\kern-0.075em}} \\ \phantom{0}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}32 & \\ \phantom{0}\underline{32} & \\ \phantom{00}0 & \end{array}\] \[\begin{aligned} (840 : 4) : y &= 105 \\ \textcolor{#e03131}{\mathbf{210}} : y &= 105 \\ y &= 210 : 105 \\ y &= \textcolor{#e03131}{\mathbf{2}} \\ \text{Проверка: }(840 : 4) : 2 &= 105 \\ \textcolor{#e03131}{\mathbf{105}} &= \textcolor{#e03131}{\mathbf{105}} \end{aligned}\]
\(1)\ 60 \cdot 4 = \textcolor{#e03131}{\mathbf{240}}\text{ (км)}\)
\(2)\ 6 \cdot 4 = \textcolor{#e03131}{\mathbf{24}}\text{ (км)}\)
\(3)\ 240 + 24 = \textcolor{#e03131}{\mathbf{264}}\text{ (км)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{264}}\) км.
\[\overset{\textcolor{#808080}{\scriptstyle 2\,288\text{ кг}}}{2\text{ т }2\text{ ц }88\text{ кг}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 3\,000\text{ кг}}\kern0.25em}{+} \overset{\textcolor{#808080}{\scriptstyle 712\text{ кг}}}{7\text{ ц }12\text{ кг}} = \underline{\kern0.4em\textcolor{#e03131}{\mathbf{3}}\text{ т}\kern0.4em}\]
