Страница 21, ГДЗ по математике за 4 класс к самостоятельным и контрольным работам Лопатковой
Нумерация. Самостоятельная работа № 6. Вариант 2
\[\begin{aligned} 37\,254 &= \textcolor{#e03131}{\mathbf{30\,000 + 7\,000 + 200 + 50 + 4}} \\ 809\,060 &= \textcolor{#e03131}{\mathbf{800\,000 + 9\,000 + 60}} \\ 54\,025 &= \textcolor{#e03131}{\mathbf{50\,000 + 4\,000 + 20 + 5}} \end{aligned}\]
\(217 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 868}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 4 = 999 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 868}}}{-} 131\) \(\textcolor{#e03131}{\textbf{— верно}}\)
\(756 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 189}}\rule[-0.35em]{0pt}{0.35em}}{:} 4 = 63 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 189}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 3\) \(\textcolor{#e03131}{\textbf{— верно}}\)
\[\begin{aligned} 457\,189 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{<}}}}\hspace{0.72em}} 457\,190 & \qquad 147\,548 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 146\,548 \\ 56\,999 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{<}}}}\hspace{0.72em}} 57\,000 & \qquad 385\,513 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{<}}}}\hspace{0.72em}} 385\,531 \\ 32\,164 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{<}}}}\hspace{0.72em}} 32\,165 & \qquad 652\,148 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{<}}}}\hspace{0.72em}} 652\,248 \end{aligned}\]
\(1)\ 40 \cdot 2 = \textcolor{#e03131}{\mathbf{80}}\text{ (см)}\)
\(2)\ 80 - 40 = \textcolor{#e03131}{\mathbf{40}}\text{ (см)}\)
Ответ: на \(\textcolor{#e03131}{\mathbf{40}}\) см.
\[\textcolor{#e03131}{\boldsymbol{(6 \overset{\textcolor{#1a7f37}{1}}{+} 4) \mathrel{\overset{\textcolor{#1a7f37}{2}}{\vphantom{+}{:}}} 2 \mathbin{\overset{\textcolor{#1a7f37}{3}}{\vphantom{+}\cdot}} 3 \overset{\textcolor{#1a7f37}{4}}{-} 5 = 10}}\]