Страница 11, ГДЗ по математике за 4 класс к самостоятельным и контрольным работам Лопатковой
Арифметические действия. Самостоятельная работа № 4. Вариант 2
\[\begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{6}75 & \underline{\,5\phantom{00}\,} \\ \underline{5}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{1}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{3}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{5}\kern-0.075em}} \\ \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}17\phantom{0} & \\ \underline{15}\phantom{0} & \\ \phantom{0}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}25 & \\ \phantom{0}\underline{25} & \\ \phantom{00}0 & \end{array} \qquad \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{9}45 & \underline{\,3\phantom{00}\,} \\ \underline{9}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{3}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{1}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{5}\kern-0.075em}} \\ \phantom{0}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}4\phantom{0} & \\ \phantom{0}\underline{3}\phantom{0} & \\ \phantom{0}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}15 & \\ \phantom{0}\underline{15} & \\ \phantom{00}0 & \end{array}\] \[\begin{array}{l} \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{8}04 & \underline{\,4\phantom{00}\,} \\ \underline{8}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{2}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{0}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{1}\kern-0.075em}} \\ \phantom{00}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}4 & \\ \phantom{00}\underline{4} & \\ \phantom{00}0 & \end{array} \\ \vphantom{\underline{0}} \\ \vphantom{\underline{0}} \end{array} \qquad \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{7}68 & \underline{\,6\phantom{00}\,} \\ \underline{6}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{1}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{2}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{8}\kern-0.075em}} \\ \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}16\phantom{0} & \\ \underline{12}\phantom{0} & \\ \phantom{0}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}48 & \\ \phantom{0}\underline{48} & \\ \phantom{00}0 & \end{array}\] Проверка: \[\begin{array}{cr} & \vphantom{\overset{\bullet}{0}}135 \\ \smash{\raisebox{0.62em}{$\times$}} & 5 \\ \hline & \textcolor{#e03131}{\mathbf{6}\kern-0.075em\mathbf{7}\kern-0.075em\mathbf{5}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}315 \\ \smash{\raisebox{0.62em}{$\times$}} & 3 \\ \hline & \textcolor{#e03131}{\mathbf{9}\kern-0.075em\mathbf{4}\kern-0.075em\mathbf{5}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}201 \\ \smash{\raisebox{0.62em}{$\times$}} & 4 \\ \hline & \textcolor{#e03131}{\mathbf{8}\kern-0.075em\mathbf{0}\kern-0.075em\mathbf{4}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}128 \\ \smash{\raisebox{0.62em}{$\times$}} & 6 \\ \hline & \textcolor{#e03131}{\mathbf{7}\kern-0.075em\mathbf{6}\kern-0.075em\mathbf{8}\kern-0.075em} \end{array}\]
\(1)\ 80 \cdot 6 = \textcolor{#e03131}{\mathbf{480}}\text{ (руб.)}\)
\(2)\ 480 : 3 = \textcolor{#e03131}{\mathbf{160}}\text{ (руб.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{160}}\) руб.

\(P = (6 + 2) \cdot 2 = \textcolor{#e03131}{\mathbf{16}}\text{ (см)}\)
\(P = (5 + 3) \cdot 2 = \textcolor{#e03131}{\mathbf{16}}\text{ (см)}\)
Если \({AA = TTM}\) и \({M = TT\text{,}}\) то \({A = \rule{0pt}{1.23em}\boxed{\smash[b]{\underset{\hspace{2em}}{\textcolor{#e03131}{\boldsymbol{TT}}}}}}\)
\(\textcolor{#808080}{{AA = TTM = TTTT}}\)