Страница 10, ГДЗ по математике за 4 класс к самостоятельным и контрольным работам Лопатковой

\[\begin{array}{l} \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{5}45 & \underline{\,5\phantom{00}\,} \\ \underline{5}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{1}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{0}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{9}\kern-0.075em}} \\ \phantom{0}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}45 & \\ \phantom{0}\underline{45} & \\ \phantom{00}0 & \end{array} \\ \vphantom{\underline{0}} \\ \vphantom{\underline{0}} \end{array} \qquad \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{8}49 & \underline{\,3\phantom{00}\,} \\ \underline{6}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{2}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{8}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{3}\kern-0.075em}} \\ \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}24\phantom{0} & \\ \underline{24}\phantom{0} & \\ \phantom{00}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}9 & \\ \phantom{00}\underline{9} & \\ \phantom{00}0 & \end{array}\] \[\begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{6}36 & \underline{\,4\phantom{00}\,} \\ \underline{4}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{1}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{5}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{9}\kern-0.075em}} \\ \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}23\phantom{0} & \\ \underline{20}\phantom{0} & \\ \phantom{0}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}36 & \\ \phantom{0}\underline{36} & \\ \phantom{00}0 & \end{array} \qquad \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\frown}}}{7}04 & \underline{\,2\phantom{00}\,} \\ \underline{6}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{3}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{5}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{2}\kern-0.075em}} \\ \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}10\phantom{0} & \\ \underline{10}\phantom{0} & \\ \phantom{00}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}4 & \\ \phantom{00}\underline{4} & \\ \phantom{00}0 & \end{array}\] Проверка: \[\begin{array}{cr} & \vphantom{\overset{\bullet}{0}}109 \\ \smash{\raisebox{0.62em}{$\times$}} & 5 \\ \hline & \textcolor{#e03131}{\mathbf{5}\kern-0.075em\mathbf{4}\kern-0.075em\mathbf{5}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}283 \\ \smash{\raisebox{0.62em}{$\times$}} & 3 \\ \hline & \textcolor{#e03131}{\mathbf{8}\kern-0.075em\mathbf{4}\kern-0.075em\mathbf{9}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}159 \\ \smash{\raisebox{0.62em}{$\times$}} & 4 \\ \hline & \textcolor{#e03131}{\mathbf{6}\kern-0.075em\mathbf{3}\kern-0.075em\mathbf{6}\kern-0.075em} \end{array} \qquad \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}352 \\ \smash{\raisebox{0.62em}{$\times$}} & 2 \\ \hline & \textcolor{#e03131}{\mathbf{7}\kern-0.075em\mathbf{0}\kern-0.075em\mathbf{4}\kern-0.075em} \end{array}\]

\(1)\ 50 \cdot 12 = \textcolor{#e03131}{\mathbf{600}}\text{ (р.)}\)
\(2)\ 600 : 6 = \textcolor{#e03131}{\mathbf{100}}\text{ (р.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{100}}\) р.

\(P = (5 + 1) \cdot 2 = \textcolor{#e03131}{\mathbf{12}}\text{ (см)}\)
\(P = (4 + 2) \cdot 2 = \textcolor{#e03131}{\mathbf{12}}\text{ (см)}\)

Если \({M = AAT}\) и \({T = AAAA\text{,}}\) то \({M = \rule{0pt}{1.23em}\boxed{\vphantom{\mathbf{0}}\hspace{2em}}}\)
\(\textcolor{#808080}{\text{Две буквы }{A}\text{ —}}\) \(\textcolor{#808080}{\text{половина буквы }{T}\text{,}}\) \(\textcolor{#808080}{\text{поэтому }{M}\text{ уравновешивают}}\) \(\textcolor{#808080}{\text{полторы буквы }{T}\text{ —}}\) \(\textcolor{#808080}{\text{целого числа букв}}\) \(\textcolor{#808080}{{T}\text{ нет.}}\)
\(\textcolor{#808080}{\text{Если }{T = AA}\text{:}}\)
Если \({M = AAT}\) и \({T = AA\text{,}}\) то \({M = \rule{0pt}{1.23em}\boxed{\smash[b]{\underset{\hspace{2em}}{\textcolor{#e03131}{\boldsymbol{TT}}}}}}\)