Страница 66, ГДЗ по математике за 4 класс к самостоятельным и контрольным работам Лопатковой

\[\begin{aligned} 800\,200 \overset{\textcolor{#1a7f37}{2}}{-} 105\,754 \mathrel{\overset{\textcolor{#1a7f37}{1}}{\vphantom{+}{:}}} 209 \overset{\textcolor{#1a7f37}{3}}{+} 204\,060 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{1\,003\,754}}}}} \end{aligned}\] \[\begin{array}{l} \textcolor{#1a7f37}{\mathbf{1)}} \\ \begin{array}{l|l} \mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}\overset{\mathclap{\textcolor{#1c7ed6}{\overgroup{\hphantom{\textstyle 1057}}}}}{1057}54 & \underline{\,209\,} \\ \underline{1045}\phantom{00} & \overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{5}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{0}\kern-0.075em}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#e03131}{\mathbf{6}\kern-0.075em}} \\ \phantom{00}\mathllap{\smash{\raisebox{-0.5em}{$-$}}\,}1254 & \\ \phantom{00}\underline{1254} & \\ \phantom{00000}0 & \end{array} \end{array} \qquad \begin{array}{l} \textcolor{#1a7f37}{\mathbf{2)}} \\ \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{8}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{2}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{0}}0 \\ \smash{\raisebox{0.62em}{$-$}} & \vphantom{\overset{\bullet}{0}}506 \\ \hline & \textcolor{#e03131}{\mathbf{7}\kern-0.075em\mathbf{9}\kern-0.075em\mathbf{9}\kern-0.075em\mathbf{6}\kern-0.075em\mathbf{9}\kern-0.075em\mathbf{4}\kern-0.075em} \\ & \vphantom{\underline{0}} \\ & \vphantom{\underline{0}} \end{array} \end{array} \qquad \begin{array}{l} \textcolor{#1a7f37}{\mathbf{3)}} \\ \begin{array}{cr} & \vphantom{\overset{\bullet}{0}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{7}}\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{9}}9\overset{\textcolor{#1c7ed6}{\bullet}}{\textcolor{#1c7ed6}{6}}94 \\ \smash{\raisebox{0.62em}{$+$}} & \vphantom{\overset{\bullet}{0}}204060 \\ \hline & \textcolor{#e03131}{\mathbf{1}\kern-0.075em\mathbf{0}\kern-0.075em\mathbf{0}\kern-0.075em\mathbf{3}\kern-0.075em\mathbf{7}\kern-0.075em\mathbf{5}\kern-0.075em\mathbf{4}\kern-0.075em} \\ & \vphantom{\underline{0}} \\ & \vphantom{\underline{0}} \end{array} \end{array}\]

\[\overset{\textcolor{#808080}{\scriptstyle 154\,000\text{ м}}}{154\text{ км}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 134\,613\text{ м}}\kern0.25em}{-} \overset{\textcolor{#808080}{\scriptstyle 19\,387\text{ м}}}{19\text{ км }387\text{ м}} = \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{134}}}}}\text{ км }\boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{613}}}}}\text{ м}\] \[\overset{\textcolor{#808080}{\scriptstyle 3\,397\text{ см}}}{33\text{ м }97\text{ см}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 6\,066\text{ см}}\kern0.25em}{+} \overset{\textcolor{#808080}{\scriptstyle 2\,669\text{ см}}}{26\text{ м }69\text{ см}} = \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{60}}}}}\text{ м }\boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{66}}}}}\text{ см}\] \[\overset{\textcolor{#808080}{\scriptstyle 955\text{ с}}}{15\text{ мин }55\text{ с}} \overset{\kern0.25em\textcolor{#808080}{\scriptstyle 897\text{ с}}\kern0.25em}{-} 58\text{ с} = \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{14}}}}}\text{ мин }\boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{57}}}}}\text{ с}\]

\(1)\ 91 - 83 = \textcolor{#e03131}{\mathbf{8}}\text{ (чел.)}\)
\(2)\ 960 : 8 = \textcolor{#e03131}{\mathbf{120}}\text{ (р.)}\)
\(3)\ 83 + 91 = \textcolor{#e03131}{\mathbf{174}}\text{ (чел.)}\)
\(4)\ 120 \cdot 174 = \textcolor{#e03131}{\mathbf{20\,880}}\text{ (р.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{20\,880}}\) р.

\(1)\ 39\,072 : 12 = \textcolor{#e03131}{\mathbf{3\,256}}\text{ (м)}\)
\(2)\ P = (3\,256 + 12) \cdot 2 = \textcolor{#e03131}{\mathbf{6\,536}}\text{ (м)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{6\,536}}\) м.