Страница 52, ГДЗ по математике за 4 класс к самостоятельным и контрольным работам Лопатковой
Умножение и деление на числа, оканчивающиеся нулями. Самостоятельная работа № 19. Вариант 1
\[\begin{aligned} 32\,000 : 800 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{40}}}}} & \qquad 493 : 70 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{7}}\ (\text{ост. }\textcolor{#e03131}{\mathbf{3}})}}} \\ 27\,000 : 900 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{30}}}}} & \qquad 645 : 80 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{8}}\ (\text{ост. }\textcolor{#e03131}{\mathbf{5}})}}} \\ 4\,500 : 90 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{50}}}}} & \qquad 546 : 90 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{6}}\ (\text{ост. }\textcolor{#e03131}{\mathbf{6}})}}} \\ 7\,200 : 80 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{90}}}}} & \qquad 368 : 40 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{9}}\ (\text{ост. }\textcolor{#e03131}{\mathbf{8}})}}} \\ 3\,600 : 400 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{9}}}}} & \qquad 186 : 20 &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{9}}\ (\text{ост. }\textcolor{#e03131}{\mathbf{6}})}}} \end{aligned}\]
\[\begin{aligned} 16\,520\text{ м} &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{16}}}}}\text{ км }\boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{520}}}}}\text{ м} \\ 156\text{ с} &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2}}}}}\text{ мин }\boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{36}}}}}\text{ с} \\ 2\,030\text{ кг} &= \boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{2}}}}}\text{ т }\boxed{\smash[b]{\underset{\hspace{4em}}{\textcolor{#e03131}{\mathbf{30}}}}}\text{ кг} \end{aligned}\]
\(1)\ 12 + 10 = \textcolor{#e03131}{\mathbf{22}}\text{ (км/ч)}\)
\(2)\ 66 : 22 = \textcolor{#e03131}{\mathbf{3}}\text{ (ч)}\)
Ответ: через \(\textcolor{#e03131}{\mathbf{3}}\) ч.
\[\textcolor{#e03131}{\mathbf{200}}\textcolor{#e03131}{\mathbf{,}}\ \textcolor{#e03131}{\mathbf{400}}\textcolor{#e03131}{\mathbf{,}}\ \textcolor{#e03131}{\mathbf{600}}\textcolor{#e03131}{\mathbf{,}}\ \textcolor{#e03131}{\mathbf{800}}\]