Страница 48, ГДЗ по математике за 3 класс к проверочным работам Волковой. Серия "Школа России" к УМК Моро
Внетабличное умножение и деление. Проверочная работа 1. Вариант 1
\[\begin{array}{|c|c|c|c|c|c|} \hline \text{Множитель} & 30 & 3 & 2 & 10 & \rule[-0.52em]{0pt}{1.66em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{1}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} \\ \hline \text{Множитель} & 2 & \rule[-0.52em]{0pt}{1.66em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{3}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} & 50 & \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{7}}\kern0.035em} & 8 \\ \hline \text{Произведение} & \rule[-0.52em]{0pt}{1.66em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{6}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} & 90 & \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{1}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} & 70 & 80 \\ \hline \end{array}\]
\[\begin{aligned} (8 + 5) \overset{\mathclap{\textcolor{#808080}{\scriptstyle 52}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 4 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 8 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 28}}}{+} 4 \cdot 5 & \qquad 7 \cdot 2 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 20}}}{+} 3 \cdot 2 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{=}}}}\hspace{0.72em}} 10 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 20}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 2 \end{aligned}\]
\[\begin{aligned} 24 \cdot 2 &= \textcolor{#e03131}{\mathbf{48}} & \qquad 16 \cdot 3 &= \textcolor{#e03131}{\mathbf{48}} & \qquad 3 \cdot 25 &= \textcolor{#e03131}{\mathbf{75}} \end{aligned}\]
\(1)\ 24 : 3 = \textcolor{#e03131}{\mathbf{8}}\text{ (р.)}\)
\(2)\ 40 : 8 = \textcolor{#e03131}{\mathbf{5}}\text{ (а.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{5}}\) альбомов.
\(1)\ 16 \cdot 4 = \textcolor{#e03131}{\mathbf{64}}\text{ (дм)}\)
\(2)\ 64 + 6 = \textcolor{#e03131}{\mathbf{70}}\text{ (дм)}\)
\(3)\ 70 : 7 = \textcolor{#e03131}{\mathbf{10}}\text{ (част.)}\)
Ответ: на \(\textcolor{#e03131}{\mathbf{10}}\) частей.
