Страница 37, ГДЗ по математике за 3 класс к проверочным работам Волковой. Серия "Школа России" к УМК Моро
Умножение и деление (продолжение). Площадь прямоугольника (квадрата). Проверочная работа 4. Вариант 2
\[\begin{aligned} &\begin{aligned} 1) & & 0 \cdot 9 &= \textcolor{#e03131}{\mathbf{0}} & \qquad 30 \cdot 1 &= \textcolor{#e03131}{\mathbf{30}} & \qquad 15 : 15 &= \textcolor{#e03131}{\mathbf{1}} \\ & & 1 \cdot 20 &= \textcolor{#e03131}{\mathbf{20}} & \qquad 10 \cdot 0 &= \textcolor{#e03131}{\mathbf{0}} & \qquad 37 + 0 &= \textcolor{#e03131}{\mathbf{37}} \\ & & 0 : 10 &= \textcolor{#e03131}{\mathbf{0}} & \qquad 9 : 9 &= \textcolor{#e03131}{\mathbf{1}} & \qquad 54 - 0 &= \textcolor{#e03131}{\mathbf{54}} \end{aligned} \\[10pt] &\begin{aligned} 2) & & (42 \overset{\textcolor{#1a7f37}{1}}{-} 20) \mathbin{\overset{\textcolor{#1a7f37}{2}}{\vphantom{+}\cdot}} 1 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{2}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{2}}\kern0.035em} & \qquad 60 \mathbin{\overset{\textcolor{#1a7f37}{1}}{\vphantom{+}\cdot}} 1 \overset{\textcolor{#1a7f37}{2}}{+} 39 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{9}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{9}}\kern0.035em} \end{aligned} \end{aligned}\]
\[\begin{aligned} 19 \cdot 1 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 38}}}{+} 19 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 1 \cdot 19 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 0}}}{-} 19 & \qquad 7 \cdot 5 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 42}}}{+} 7 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 7 \cdot 5 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 40}}}{+} 5 \\ 72 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 0}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 0 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{<}}}}\hspace{0.72em}} 72 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 72}}}{-} 0 & \qquad 4 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 36}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 9 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{<}}}}\hspace{0.72em}} 4 \cdot 9 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 40}}}{+} 4 \end{aligned}\]
\(1)\ 3 \cdot 7 = \textcolor{#e03131}{\mathbf{21}}\text{ (м)}\)
\(2)\ 4 \cdot 6 = \textcolor{#e03131}{\mathbf{24}}\text{ (м)}\)
\(3)\ 21 + 24 = \textcolor{#e03131}{\mathbf{45}}\text{ (м)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{45}}\) м.
\[\begin{aligned} b \overset{\mathclap{\textcolor{#808080}{\scriptstyle 0}}}{-} b &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{=}}}}\hspace{0.72em}} b \overset{\mathclap{\textcolor{#808080}{\scriptstyle 0}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 0 & \qquad 0 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 0}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} c &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{<}}}}\hspace{0.72em}} c \overset{\mathclap{\textcolor{#808080}{\scriptstyle 1}}\rule[-0.35em]{0pt}{0.35em}}{:} c \end{aligned}\]
