Страница 55, ГДЗ по математике за 2 класс к проверочным работам Волковой. Серия "Школа России" к УМК Моро
Умножение и деление. Проверочная работа 2. Вариант 2
\[\begin{aligned} 0 \cdot 65 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} & \quad 1 \cdot 10 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{1}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} & \quad 1 \cdot 100 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{1}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} \\ 0 \cdot 30 &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} & \quad 1 \cdot (53 + 7) &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{6}}\kern0.035em}\hspace{-0.04em}\boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} & \quad 0 \cdot (100 - 48) &= \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{0}}\kern0.035em} \end{aligned}\]
\[\begin{aligned} 8 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 40}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 5 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 8 + 8 + 8 + 8 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 37}}}{+} 5 & \qquad 12 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 36}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 3 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 12 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 15}}}{+} 3 \\ 7 \cdot 6 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{=}}}}\hspace{0.72em}} 6 \cdot 7 & \qquad 1 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 49}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 49 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 0 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 0}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 49 \\ 16 \cdot 3 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{=}}}}\hspace{0.72em}} 3 \cdot 16 & \qquad 1 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 4}}\rule[-0.35em]{0pt}{0.35em}}{\cdot} 4 &\mathrel{\hspace{0.72em}\mathclap{\vcenter{\Large\bigcirc}}\mathclap{\textcolor{#e03131}{\pmb{\boldsymbol{>}}}}\hspace{0.72em}} 1 + 1 \overset{\mathclap{\textcolor{#808080}{\scriptstyle 3}}}{+} 1 \end{aligned}\]
\(6 \cdot 3 = \textcolor{#e03131}{\mathbf{18}}\text{ (р.)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{18}}\) р.
\(5 + 2 + 5 + 2 = \textcolor{#e03131}{\mathbf{14}}\text{ (см)}\)
Ответ: \(\textcolor{#e03131}{\mathbf{14}}\) см.
Запиши в окошко такое число, при котором равенство \({7 \cdot 6 - 7 - 7 = 7 \cdot \boxed{\kern0.035em\textcolor{#e03131}{\mathbf{4}}\kern0.035em}}\) станет верным.
\(\textcolor{#808080}{7 \cdot 6 - 7 - 7 = 28\text{, }28 = 7 \cdot 4\text{.}}\)
